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A subtraction of fractionso where the denominators have no factors in common so we simpllly multiply the two together to create the LCD. Then both fractions are adjusted by multiplying each…
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Adding ratioinal expressions with quadratic denominators requires factoring each denominator so that the LCD can be determined. Then each fraction is exapanded by multiplying the tops and the…
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Shows one example of solving a iinear inequality in two steps.
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Shows how to interpret a verbal description into an mathematical equation.
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Some discussion of vocabulary combined with writing a simple expression from a verbal description.
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A more complicated version of solving an equation. It specifically addresses dealing with two variable terms on the same side of the equals sigh.
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A simpler version of an equation that needs distribution across a set of parenthese as the first step to solving for the variable
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A second look at factoring the top and bottom of a fraction in algebra that then reduces that fraction.
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This shows how to factor the numerator and denominator of a fraction in algebra so that we can reduce the same factors ono the top and the bottom because they divide to one.
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This demonstrates how some quadratic equations need to be simplified and put in standard form before the quadratic expression can be factored so the factors can be set to zero and solved.
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Demonstrates how to remove a common factor that not just a single number or variable, but a binomial i. e. a two-term expression.
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Using the quotient rule, we can eliminate the negeatiev exponent rigiht awa and then applly the "power rule".
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We use the slope formula to find the slope from the given points, then we use it again, inserting the discovered slope and solving for the desired missing coordintate of a third point.
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Describes the steps inn solving a somewhat complicated inequality, and reminds you of two things. 1) Inequalities are solved like equations except one thing. 2) That is that you must remember when…
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This shows how written statments are not always written in the order that the mathematical equivalent is, so please listen to the explanation presented here.
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A simple word problem to get us started with "distance equals rate (or speed) times time.
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