Search for tag: "matter"

Finding the final amount in a word problem on compound interest

This video gives the formula for calculating compound interest and then demonstrates how to calculate the future amount after a given number of years.

From  Tom Grant 11 plays 0  

Adding rational expressions with multivariate monomial denominators: Basic

This example shows how to factor each denominator and then determine which of these factors are needed to create the least common denominator (LCD). Then the fractions are expanded by multiplying…

From  Tom Grant 6 plays 0  

Simplifying a ratio of linear polynomials: 1, -1, and no simplification

This shows four examples just to cover a variety of "looks". There is at least one of each tyoe,

From  Tom Grant 11 plays 0  

Solving for a variable in terms of other variables using addition or subtraction: Advanced

Describes how to rearrange a simple formula with several variables so that a different and particular one is isolated.

From  Tom Grant 8 plays 0  

Solving a linear equation with several occurrences of the variable: Variables on both sides and distribution

A somewhat fancierversion of seveal solving equation versions that should help solidify the process in your mind.

From  Tom Grant 11 plays 0  

Word problem involving the Pythagorean Theorem

Application of the equation relating the three sides of a right triangle:: a^2 + b^2 = c^2 where a and b are the shorter sides that make the rigiht angle and c is the lenght of the longest side.

From  Tom Grant 18 plays 0  

Finding the roots of a quadratic equation with leading coefficient greater than 1

This is a quadractic equation that can be factored to solve it. The zero product property allows writing the factors each equal to 0 and then solving those linear equatioins.

From  Tom Grant 11 plays 0  

Identifying solutions to a linear inequallity in two variables

Just an exercise in testing whether an ordered pair makes an inequality statement true when plugged in for the variables.

From  Tom Grant 11 plays 0  

Finding slopes of lines parallel and perpendicular to a line given in the form Ax + By = C

Shows how to convert Ax + By = C to y = mx + b then what and why the slopes for parallell and perpendicular lintes are what they are.

From  Tom Grant 20 plays 0