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01:44 Adding rational expressions with common… Adding rational expressions with common denominators & GCF factoring	Adding rational expressions with common denominators & GCF factoring An example that is easy to combine with subtraction, in this case, because the two fractions have common denominators. However, be aware that there may be a way to simplifying the answer further. … math math emporium gcf factor common denominator b. answer minus expressions lancer bottom factors tops denominators fractions From Tom Grant 6 plays 0
02:28 Dividing rational expressions involving… Dividing rational expressions involving multivariate monomials	Dividing rational expressions involving multivariate monomials A quick justification of dividing fractions by multiplying by the reciprocal of the second fraction in the division followed by an example that involves reducing the common factors in the numerator… math math emporium fraction monomial factor reducing fractions cubed bottom times fractions change multiplication division answer b. exponent reduces instance result denominator numerator x. flip thing variables From Tom Grant 5 plays 0
02:18 Quotient rule with negative exponents: Problem… Quotient rule with negative exponents: Problem type 2	Quotient rule with negative exponents: Problem type 2 A multi-variable fraction that is reduced by applying the quotient rule and the definition of a negative exponent. math math emporium negative exponent quotient rule exponent bottom fraction base rule answer quotient b. end definition side beginning eighths expression From Tom Grant 4 plays 0
02:58 Solving a word problem involving a sum and… Solving a word problem involving a sum and another basic relationship using a system of lineaer equations	Solving a word problem involving a sum and another basic relationship using a system of lineaer equations This demo discusses how to set up two equations to solve the situation described, and then choose the best method to use to solve for each of the variables. math math emporium system substitution biology textbooks sides variable phrase b. solo method application total variables equations problem word From Tom Grant 7 plays 0
02:39 Writing an equation in slope-intercept form given… Writing an equation in slope-intercept form given the slope and a point	Writing an equation in slope-intercept form given the slope and a point This shows the method of using the point-slope form to write the equation, then solving that form for y to get y = mx + b. math math emporium slope point point-slope form slope-intercept form y=mx+b times form thirds equation threes b. answer mx sides bottom intersect method benefit minus ways equals From Tom Grant 19 plays 0
01:30 Writing an equation and graphing a line given its… Writing an equation and graphing a line given its slope and y-intercept	Writing an equation and graphing a line given its slope and y-intercept The informaton given here can be entered directly into the y = mx + b or slope-intercept form. Then the y-intercept is used as a starting point where you apply rise over run to the given slope to… math math emporium graph slope y-intercept y=mx+b halves change b. points left coordinate rises run bottom rise negatives mx form graphic equation From Tom Grant 5 plays 0
04:06 Finding the maximum or minimum of a quadratic… Finding the maximum or minimum of a quadratic function	Finding the maximum or minimum of a quadratic function This shows how to decide whether you are seeking a maximum or minimum value for a quadratic function and then how to find the vertex of i ts parabola to deternine the x-value that locates the min… math math emporium vertex minimum maximum function times answers point directions a. thing x. minus areas b. formula words input occur answer corner From Tom Grant 7 plays 0
06:21 Solving for a variable in terms of other… Solving for a variable in terms of other variables in a rational equation: Problem type 3	Solving for a variable in terms of other variables in a rational equation: Problem type 3 This one demonstrates how to eliminate the rational parts of the equation as usual, then gather the terms with the chosen variable on one side of the equal sign so that it can be factored to one… math math emporium gcf factoring lcd b. minus times side bc sides answer bp room quantity aac variable bs equals denominator thing fractions equation equations ap From Tom Grant 18 plays 0
02:25 Adding rational expressions with denominators ax… Adding rational expressions with denominators ax - b and b - ax	Adding rational expressions with denominators ax - b and b - ax Describes how to deal with denominators that are simply opposite in sign when adding or subtracting fractional expressions. math math emporium adding rational expressions opposite expressions minus times bottom ax denominators expressions answer signs result pattern numerator fraction denominator opposites x. b. form From Tom Grant 13 plays 0
02:22 Pythagorean Theorem Pythagorean Theorem	Pythagorean Theorem A quick run through the use of a^2 + b^2 = c^2 to find an unknown side of a right tirangle if we know the other two sides. math math emporium a^2 + b^2 = c^2 pythagorean theorem square root sides root angle triangle calculator length minus square formula b. a. colony equals hypotenuse side corner symbol egyptians mesopotamians china From Tom Grant 13 plays 0
02:56 Multiplying conjugate binomials: Univariate Multiplying conjugate binomials: Univariate	Multiplying conjugate binomials: Univariate Demonstrates what happens when the F.O.I.L. method is applied to multiply two binomails of the form (a + b) (a - b). It's special circumstance that allows a short cut. math math emporium algebra f.o.i.l. method (a+b)(a-b) times minus x. signs binomials term situation rule b. ab quantity generic bone binomial pattern answer coefficient middle square method From Tom Grant 23 plays 0
06:58 Solving a word problem using a system of linear… Solving a word problem using a system of linear equations of the form Ax + By = C	Solving a word problem using a system of linear equations of the form Ax + By = C Talks about how to interpret the words to create two equations, then solves them together using the elimination method, making opposites of one variable's terms sot that the equations can be… math math emporium algebra word problem system of equations elimination method hours plan clients wednesday b. thursday sentence equation total calculator plans workout times halves bottom things opposites y. thing side From Tom Grant 16 plays 0
04:13 Classifying systems of linear equations from… Classifying systems of linear equations from graphs	Classifying systems of linear equations from graphs Looks at the three types of graphs that can occur with a system of two linear equaltions in two variables. math math emporium algebra system of equations y = mx + b consistent dependent consistent independent inconsistent equations solution answers solutions words graph slope rest answer variables types systems intercepts lines intercept points boxes coordinate point From Tom Grant 17 plays 0
05:42 Identifying solutions to a system of linear… Identifying solutions to a system of linear equations	Identifying solutions to a system of linear equations This demonstrates testing possible answers to a system of two equations to see whether they are truly answers or not. Note that each answer has to work for both equations, but if it doesn't… math math emporium algebra solution system of equations times ratio equations button mistake checks minus b. buttons synsets thing kind functions linear space track systems solutions spot From Tom Grant 14 plays 0
02:11 Graphing a function of the form f (x) = ax + b:… Graphing a function of the form f (x) = ax + b: Fractional slope	Graphing a function of the form f (x) = ax + b: Fractional slope Shows how thits form is simply the same as y = mx + b, and then writes the slope and y-intercpt down. It ends with using these to graph the line of points that satisfy this function. math math emporium algebra slope y=intercept graph thirds function point x. form ruler negatives room points times b. thing minus From Tom Grant 62 plays 0
03:52 Finding slopes of lines parallel and… Finding slopes of lines parallel and perpendicular to a line given in the form Ax + By = C	Finding slopes of lines parallel and perpendicular to a line given in the form Ax + By = C Shows how to convert Ax + By = C to y = mx + b then what and why the slopes for parallell and perpendicular lintes are what they are. math math emporium algebra slope parallel perpendicular ax + by = c y = mx + b term sevenths negatives piece y. equation equals reciprocals tangent flip run fact matter rise lot angle fraction worksheet From Tom Grant 19 plays 0